 |
Before we can
discuss stereoisomers, we need to understand chirality. |
|
 |
Chirality is the property of
"handness". |
|
|
|
Consider your hands. They are very similar structures, the fingers
of each hand extend from the top edge of each palm, while the tumbs extend from the side.
|
|
|
|
Yet your hands are not identical... they can not be
superimposed on top of each other.
|
|
|
|
Look closely... your hands are mirror images of each other.
|
|
|
 |
Organic molecules can be chiral
if they contain one or more chiral centers. |
|
|
|
|
A chiral center is defined as an sp3 hybridized carbon
that is bonded to four different groups.
|
|
|
|
Consider the compound 2-bromobutane: |
|
|
Model (cpk / ball & stick) |
| Mark
chiral center (on / off) |
|
|
|
The carbon which is bound to the bromine (the red atom) is a chiral
center.
|
|
|
|
It is sp3 hybridized and it is bound to four different
groups: a hydrogen (white), a bromine (red), a methyl (-CH3) group and an ethyl
(-CH2CH3) group.
|
|
|
|
The other carbons in this structure are not chiral centers. They are
all sp3 hybridized, but each is bonded to at least two hydrogens.
|
|
|
 |
2-Fluoro-3-bromobutane has two chiral
centers: |
|
|
|
| |
|
|
|
The second carbon (C-2) in this molecule (attached to the yellow
iodine atom) is sp3 hybridized and bears four different groups: a hydrogen, a
fluorine, a methyl group and a -CHBrCH3 group.
|
|
|
|
Likewise, the third carbon (C-3, attached to the red bromine) is
also sp3 hybridized and bears four different groups: a hydrogen, a bromine, a
methyl group and a -CHFCH3 group.
|
|
|
|
The remaining carbons (C-1 and C-4) are both sp3
hybridized but each bears three hydrogens, thus neither is a chiral center.
|
|
|
 |
If a molecule
possess at least one chiral center the possibility of stereoisomers exists. |
|
|
|